phil scott wrote:
> On Mar 6, 5:25 pm, pg <pen...@[EMAIL PROTECTED]
> wrote:
>
>>On Mar 6, 11:12 am, GerryL <gerry.li...@[EMAIL PROTECTED]
> wrote:
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>>>On Mar 5, 8:22 pm, pg <pen...@[EMAIL PROTECTED]
> wrote:
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>>>>On Mar 6, 5:36 am, Roader857 <stonechi...@[EMAIL PROTECTED]
> wrote:
>>
>>>>>Which is more dangerous exposed leads in a 500 W power supply or a 12
>>>>>V automotive battery? and Why?
>>
>>>>You got Watt. You got Volt. What you need is Amp.
>>
>>>>It's the key.
>>
>>>>You can have a 500W power supply, but if the amp is only 0.0001mA,
>>>>that power supply would give you a shock of your life, but at least
>>>>you'll survive.
>>
>>>Assuming we're talking about danger to a human, then can we use an
>>>estimate of the resistance of a human body to work out what the
>>>current would be in each case?
>>
>>What drives through the "resistance" is actually the voltage. Current
>>is measured in Amperes, and it stands for the amount of electrons.
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> closer but no cigar
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> current is the product of volts x amps. same as watts,
>
> you are right about amps and about vottage though
To some extent, electricity is analagous to hydraulics.
Voltage is pressure, and amperage (current) is flow. The higher the
pressure, the
more flow for a given resistance (restriction). When it comes to
electrocution,
what kills you is current, the flow of electrons through your body.
Mark M.
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> Phil Scott
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>>If the voltage is high, and the current is very low, you will get a
>>shock, but since the number of electrons is relative low, normally it
>>won't kill the person.
>>
>>However, if the voltage is high, and the current is high too, it'd be
>>an electrocution. Electron flows through the body is so large that
>>they fried the body.- Hide quoted text -
>>
>>- Show quoted text -
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